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Thread: Formation Takeoff with Cross wind >5kts

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  1. #1
    Member Frodo's Avatar
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    I use the current weather wind direction and speed to determine the lineup for departure.

  2. #2
    Quote Originally Posted by Frodo View Post
    I use the current weather wind direction and speed to determine the lineup for departure.
    Hey Frodo,

    476TTp3-3.A10C:
    "When crosswind component exceed 5 knots, wingman on the upwind side of the runway."

    My point is that to determine the "crosswind-component" you must do some math...

    crosswind_component = sine(wind_angle_off_runway_heading) x wind_speed


    Note that a 25 knot wind at 10 deg off runway heading only produces 4.34 knots of crosswind-component, which is under the 5 knot crosswind-component limit, and therefore either side of the runway could be occupied by the lead ship.

    Additional examples:
    When 6 knot wind direction is 90 deg off runway heading (beam to runway) exceeds the 5 knot and therefore the lead must take the downwind side as specified in the TTP. When wind direction is 90deg to runway heading (beam to runway), crosswind_component = wind_speed

    When 6 knot wind direction is 45 deg off runway heading, crosswind_component is 4.24 knot and therefore less than the limit, and no factor.

    Crosswind-component - Although not specifically defined in the TTP, I interpret this to be the calculated wind vector component (using my formula above) that is 90 deg to the runway heading.

    At least that's how I interpret the TTP. I could be wrong, of course.

    Are people doing the calculation above to determine the crosswind-component in preflight?
    Last edited by Stryker; 28Jun18 at 17:31. Reason: clarify - 90deg to runway heading (beam to runway)

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