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Member
This makes me think of another related topic... takeoff rotation speed... calculated based on weight and drag in the MDC.
Does this takeoff rotation speed factor in the "headwind-component" of the prevailing wind conditions?
headwind_component = cosine(wind_angle_off_runway_heading) x wind_speed
If the headwind_component is not factored in to the rotation speed calculation, then we should be subtracting the headwind_component from rotation speed to get the effective-rotation-speed for takeoff?
mdc_rotation_speed - headwind_component = effective_rotation_speed
So for example, if wind conditions are 25 knot wind at 10 deg off runway heading, then headwind_component is 24.6 knots of wind coming towards you on the runway.
Given that your rotation speed was calculated to be 130 knots, then
130 - 24.6 = 105.4 knots (effective-rotation-speed)
105 knots (effective-rotation-speed)
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